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`span_to_snippet` return value is a `Result`, not an `Option`

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Zack M. Davis 2018-06-30 08:37:15 -07:00 committed by Who? Me?!
parent 5774db6f3a
commit badbb2daec
1 changed files with 2 additions and 2 deletions
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4
src/diag.md
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@ -56,7 +56,7 @@ let mut err = sess.struct_span_err(sp, "oh no! this is an error!");
// In some cases, you might need to check if `sp` is generated by a macro to
// avoid printing weird errors about macro-generated code.
if let Some(snippet) = sess.codemap().span_to_snippet(sp) {
if let Ok(snippet) = sess.codemap().span_to_snippet(sp) {
// Use the snippet to generate a suggested fix
err.span_suggestion(suggestion_sp, "try using a qux here", format!("qux {}", snip));
} else {
@ -90,7 +90,7 @@ For example, to make our `qux` suggestion machine-applicable, we would do:
```rust,ignore
let mut err = sess.struct_span_err(sp, "oh no! this is an error!");
if let Some(snippet) = sess.codemap().span_to_snippet(sp) {
if let Ok(snippet) = sess.codemap().span_to_snippet(sp) {
// Add applicability info!
err.span_suggestion_with_applicability(
suggestion_sp,