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Use fewer stages in bootstrapping docs 

After https://github.com/rust-lang/rust/pull/73964, they're redundant.
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Joshua Nelson 2020-08-30 22:09:57 -04:00 committed by Tshepang Lekhonkhobe
parent f6b1f9d49d
commit 4411cf2001
1 changed files with 2 additions and 2 deletions
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src/building/bootstrapping.md
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@ -25,7 +25,7 @@ The `stage2` compiler is the one distributed with `rustup` and all other
install methods. However, it takes a very long time to build because one must install methods. However, it takes a very long time to build because one must
first build the new compiler with an older compiler and then use that to first build the new compiler with an older compiler and then use that to
build the new compiler with itself. For development, you usually only want build the new compiler with itself. For development, you usually only want
the `stage1` compiler: `x.py build --stage 1 library/std`. the `stage1` compiler: `x.py build library/std`.
## Complications of bootstrapping ## Complications of bootstrapping
@ -196,7 +196,7 @@ later copied into stage2 as well (both the compiler's `libdir` and the
This `std` is pretty much necessary for any useful work with the compiler. This `std` is pretty much necessary for any useful work with the compiler.
Specifically, it's used as the `std` for programs compiled by the newly compiled Specifically, it's used as the `std` for programs compiled by the newly compiled
compiler (so when you compile `fn main() { }` it is linked to the last `std` compiler (so when you compile `fn main() { }` it is linked to the last `std`
compiled with `x.py build --stage 1 library/std`). compiled with `x.py build library/std`).
The `rustc` generated by the stage0 compiler is linked to the freshly-built The `rustc` generated by the stage0 compiler is linked to the freshly-built
`std`, which means that for the most part only `std` needs to be cfg-gated, `std`, which means that for the most part only `std` needs to be cfg-gated,