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cmd/compile: fix line number for implicitly declared method expressions
Method expressions where the method is implicitly declared have no line number. The Error method of the built-in error type is one such method. We leave the line number at the use of the method expression in this case. Fixes #29389 Change-Id: I29c64bb47b1a704576abf086599eb5af7b78df53 Reviewed-on: https://go-review.googlesource.com/c/155639 Run-TryBot: Keith Randall <khr@golang.org> TryBot-Result: Gobot Gobot <gobot@golang.org> Reviewed-by: Ian Lance Taylor <iant@golang.org>
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@ -439,9 +439,14 @@ func makepartialcall(fn *Node, t0 *types.Type, meth *types.Sym) *Node {
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// Set line number equal to the line number where the method is declared.
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var m *types.Field
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if lookdot0(meth, rcvrtype, &m, false) == 1 {
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if lookdot0(meth, rcvrtype, &m, false) == 1 && m.Pos.IsKnown() {
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lineno = m.Pos
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}
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// Note: !m.Pos.IsKnown() happens for method expressions where
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// the method is implicitly declared. The Error method of the
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// built-in error type is one such method. We leave the line
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// number at the use of the method expression in this
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// case. See issue 29389.
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tfn := nod(OTFUNC, nil, nil)
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tfn.List.Set(structargs(t0.Params(), true))
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@ -0,0 +1,17 @@
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// compile
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// Copyright 2018 The Go Authors. All rights reserved.
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// Use of this source code is governed by a BSD-style
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// license that can be found in the LICENSE file.
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// Make sure we can correctly compile method expressions
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// where the method is implicitly declared.
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package main
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import "io"
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func main() {
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err := io.EOF
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_ = err.Error
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}
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