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cmd/compile: add a flag to print the source line for generated rules 

When working on rulegen, I often find myself
searching the rules files to find the source of
generated code. Add a flag to make that easier.

The flag needs to be off by default,
so that adding a single rule doesn't cause a massive diff.

Change-Id: I5a6f09129dc6fceef7c9cd1ad7eee24f3880ba91
Reviewed-on: https://go-review.googlesource.com/c/go/+/213700
Run-TryBot: Josh Bleecher Snyder <josharian@gmail.com>
Reviewed-by: Keith Randall <khr@golang.org>
This commit is contained in:
Josh Bleecher Snyder 2020-01-06 13:43:51 -08:00
parent 49f8d45994
commit 24fa159a2e
1 changed files with 7 additions and 1 deletions
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8
src/cmd/compile/internal/ssa/gen/rulegen.go
View File

@ -54,7 +54,10 @@ import (
// If multiple rules match, the first one in file order is selected.
var genLog = flag.Bool("log", false, "generate code that logs; for debugging only")
var (
genLog = flag.Bool("log", false, "generate code that logs; for debugging only")
addLine = flag.Bool("line", false, "add line number comment to generated rules; for debugging only")
)
type Rule struct {
rule string
@ -598,6 +601,9 @@ func fprint(w io.Writer, n Node) {
fprint(w, n)
}
case *RuleRewrite:
if *addLine {
fmt.Fprintf(w, "// %s\n", n.loc)
}
fmt.Fprintf(w, "// match: %s\n", n.match)
if n.cond != "" {
fmt.Fprintf(w, "// cond: %s\n", n.cond)