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reflect: rtype.MethodByName using binary search
Change-Id: If36e9fd7d6b1993ca2d0d382e7fa52212170c798 Reviewed-on: https://go-review.googlesource.com/c/go/+/425481 Auto-Submit: Ian Lance Taylor <iant@google.com> Run-TryBot: Ian Lance Taylor <iant@google.com> Reviewed-by: Cherry Mui <cherryyz@google.com> Reviewed-by: Ian Lance Taylor <iant@google.com> TryBot-Result: Gopher Robot <gobot@golang.org>
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@ -2384,6 +2384,16 @@ func TestMethod(t *testing.T) {
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t.Errorf("NoArgs returned %d values; want 0", n)
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}
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_, ok = TypeOf(&p).MethodByName("AA")
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if ok {
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t.Errorf(`MethodByName("AA") should have failed`)
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}
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_, ok = TypeOf(&p).MethodByName("ZZ")
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if ok {
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t.Errorf(`MethodByName("ZZ") should have failed`)
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}
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// Curried method of value.
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tfunc := TypeOf((func(int) int)(nil))
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v := ValueOf(p).Method(1)
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@ -892,12 +892,26 @@ func (t *rtype) MethodByName(name string) (m Method, ok bool) {
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if ut == nil {
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return Method{}, false
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}
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// TODO(mdempsky): Binary search.
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for i, p := range ut.exportedMethods() {
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if t.nameOff(p.name).name() == name {
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return t.Method(i), true
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methods := ut.exportedMethods()
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// We are looking for the first index i where the string becomes >= s.
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// This is a copy of sort.Search, with f(h) replaced by (t.nameOff(methods[h].name).name() >= name).
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i, j := 0, len(methods)
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for i < j {
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h := int(uint(i+j) >> 1) // avoid overflow when computing h
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// i ≤ h < j
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if !(t.nameOff(methods[h].name).name() >= name) {
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i = h + 1 // preserves f(i-1) == false
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} else {
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j = h // preserves f(j) == true
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}
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}
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// i == j, f(i-1) == false, and f(j) (= f(i)) == true => answer is i.
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if i < len(methods) && name == t.nameOff(methods[i].name).name() {
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return t.Method(i), true
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}
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return Method{}, false
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}
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